WebDec 10, 2024 · If tanθ = cotθ = a and sinθ + cos θ = b, then solve (b^2 - 1)^2(a^2 + 4). asked Dec 7, 2024 in Trigonometry by RiteshBharti ( 54.1k points) trigonometric identities WebDec 10, 2024 · If tanθ = cotθ = a and sinθ + cos θ = b, then solve (b^2 - 1)^2(a^2 + 4). asked Dec 7, 2024 in Trigonometry by RiteshBharti ( 54.1k points) trigonometric identities
Write the value of `cot^2theta-1/(sin^2theta)` - Sarthaks
WebOct 21, 2024 · If cot theta - 1 / cot theta +1 =1-root 3 / 1+root 3. Find the acute angle Get the answers you need, now! Jahnabeedatta Jahnabeedatta 22.10.2024 Math Secondary … Webcot (θ) = −1 cot ( θ) = - 1. Take the inverse cotangent of both sides of the equation to extract θ θ from inside the cotangent. θ = arccot(−1) θ = arccot ( - 1) Simplify the right side. Tap for more steps... θ = 3π 4 θ = 3 π 4. The cotangent function is negative in the second and fourth quadrants. To find the second solution ... drawing pete the cat
Solved ify the identity tan(θ)cos(θ)sec(θ)=cot(θ) uestion 2 - Chegg
WebClick here👆to get an answer to your question ️ that \( \tan ^ { 3 } \theta \) \( 1 + \tan ^ { 2 } \theta \) \( \cot ^ { 3 } \theta \) \( 1 + \cot ^ { 2 } \theta ... WebClick here👆to get an answer to your question ️ Prove that : (1 + cot^2 theta)· (1 - cos theta) · (1 + cos theta) = 1 WebSep 21, 2015 · cot^2 theta Let's see, we have: (csc^2 theta)/(1+tan^2 theta) In this case, I would probably start by rewriting everything in terms of sines and cosines, since we know that tan theta = sin theta/cos theta and csc theta = 1/sin theta So we now have: = (1/sin^2 theta) / (1+ sin^2 theta /cos^2 theta) Here, I notice that the denominator can be … drawing phase portraits